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0=12x^2-60x+70
We move all terms to the left:
0-(12x^2-60x+70)=0
We add all the numbers together, and all the variables
-(12x^2-60x+70)=0
We get rid of parentheses
-12x^2+60x-70=0
a = -12; b = 60; c = -70;
Δ = b2-4ac
Δ = 602-4·(-12)·(-70)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{15}}{2*-12}=\frac{-60-4\sqrt{15}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{15}}{2*-12}=\frac{-60+4\sqrt{15}}{-24} $
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